Matematikë

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diEllzz
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Re: Matematikë

Post by diEllzz »

a spriton najkush me mi ngjidh qeto :

a) tg1+tg5+tg9+...+tg177=45
b)cosπ/7-cos2π/7+cos3π/7=1/2
c)cos24+cos48-cos84-cos12=1/2
d)cos55·cos65+cos65·cos175+cos175·cos55=-3/4
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David Gilmour
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Re: Matematikë

Post by David Gilmour »

diEllzz wrote:a spriton najkush me mi ngjidh qeto :

a) tg1+tg5+tg9+...+tg177=45
b)cosπ/7-cos2π/7+cos3π/7=1/2
c)cos24+cos48-cos84-cos12=1/2
d)cos55·cos65+cos65·cos175+cos175·cos55=-3/4
qajo e para a s'pot kujtohet zgjidhja a
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diEllzz
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Re: Matematikë

Post by diEllzz »

David Gilmour wrote:
diEllzz wrote:a spriton najkush me mi ngjidh qeto :

a) tg1+tg5+tg9+...+tg177=45
b)cosπ/7-cos2π/7+cos3π/7=1/2
c)cos24+cos48-cos84-cos12=1/2
d)cos55·cos65+cos65·cos175+cos175·cos55=-3/4
qajo e para a s'pot kujtohet zgjidhja a
le tash i bona :D
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David Gilmour
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Re: Matematikë

Post by David Gilmour »

diEllzz wrote:
David Gilmour wrote:
diEllzz wrote:a spriton najkush me mi ngjidh qeto :

a) tg1+tg5+tg9+...+tg177=45
b)cosπ/7-cos2π/7+cos3π/7=1/2
c)cos24+cos48-cos84-cos12=1/2
d)cos55·cos65+cos65·cos175+cos175·cos55=-3/4
qajo e para a s'pot kujtohet zgjidhja a
le tash i bona :D
sa t'dul zgjidhja
Agonn.
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Re: Matematikë

Post by Agonn. »

kush po ma zgjedh qit grafik se shum pom duhet...

y=3cos(1/3x+pi/3) pe shkru edhe ndryshe
y=3cos(x/3+pi/3)

mduhet me ja gjet
1.Fushen e Perkufizimit (infinit,-infinit) u kry
2.Perioda... mdoket i del 6pi
3.Kufizushmeria... mdoket osht -3,3
4.Zerot
5.Shenjat
6.Monotonin edhe vlerat ekstreme
7.Grafikun

kush ma zgjedh komplet mkish pshtu se shum pom duhet per neser..
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bett
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Re: Matematikë

Post by bett »

Shikoni ekuacionin matematikor ne vijim:
Ata thone se vetem njerezit me IQ 120 apo me te madhe jane ne gjendje ta zgjidhin.

Nese :
2 + 3 = 10
7 + 2 = 63
6+ 5 = 66
8+ 4 = 96

Atehere :

9 + 7 = ??????????

Numri qe ju do ta gjeni, eshte passwordi i dokumentit ne atachment. Shenojeni emrin tuaj dhe ua dergoni te tjereve.
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username
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Re: Matematikë

Post by username »

144

:P
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bett
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Re: Matematikë

Post by bett »

gjeni pse e postovee bre kaq heret :P editoje
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username
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Re: Matematikë

Post by username »

deshta me tregu qe rren koka
edhe kta ne liste krejte kokan shqiptar :P
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rock_boy18
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Re: Matematikë

Post by rock_boy18 »

qka pe dhini bre pldh me qita 2+3-10 , 7+2=63 etj etj
a mun naj kush me ma shpjegu qita ???
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hp11
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Re: Matematikë

Post by hp11 »

bett wrote:Shikoni ekuacionin matematikor ne vijim:
Ata thone se vetem njerezit me IQ 120 apo me te madhe jane ne gjendje ta zgjidhin.

Nese :
2 + 3 = 10
7 + 2 = 63
6+ 5 = 66
8+ 4 = 96

Atehere :

9 + 7 = ??????????

Numri qe ju do ta gjeni, eshte passwordi i dokumentit ne atachment. Shenojeni emrin tuaj dhe ua dergoni te tjereve.

@rokboj

2+3=10 dmth ktu i mledhim numrat 2+3 qe bojn 5 edhe i shumezojme me numrin e pare qe eshte 2 e krejt kjo eshte e barabarte me 10 dmth sipas qetij parimi jon krejt qeto barazime edhe n'fund tu shku me qet rregull del qe 9+7=144


e kom zgjidh qet sen mrena 20 ose 30 sekonda qashtu diqka
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rock_boy18
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Re: Matematikë

Post by rock_boy18 »

aha , oke Flamur thnx pra njeri :D , e kjo a esht si naj msim matematik a veq kshtu detyr logjike :P
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bett
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Re: Matematikë

Post by bett »

rok detyr logjikee osht

qe njaa teper teper teper t thjeesht
e mas ksaj shkojm me ektreme

4 4 4 4=20

perdor qfar dush sheje per me taa jap rezultatin :P
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Ago1
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Re: Matematikë

Post by Ago1 »

4!+4-4-4=20

a osht e sakt :P
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John Lennon
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Re: Matematikë

Post by John Lennon »

ose
4* (4+4/4)
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